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air density calculations...

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Old 06-17-2004, 03:07 PM
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Default air density calculations...

So I was reading something regarding turbos/intercoolers the other day, it said that the ratio of air (at intake temp) to air (post-intercooler) was something like (1 + (deltaT/273)) where deltaT is the temp. change in deg.C. So, would this mean if you lowered the air by 273 degrees from intake temp, that you'd have twice the air density and therefore approx. twice the horsepower?

Sorry if it seems like a stupid question...
Old 06-17-2004, 07:59 PM
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Default at which point...

the motor explodes! ;{) yes. but you'd have trouble producing that kind of drop. also that °C.
Old 06-18-2004, 02:16 PM
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Default 0 Kelvin = -273.15 Celcius = 0 Rankine = -459.6 Farenheit

0 Kelvin is ABSOLUTE ZERO, meaning that there would be no molecular movement, nothing. That's really really damn cold (also, an FIY to put things into perspective: 273.15 Kelvin = 0.0 Celcius = 32.0 Farenheit = 491.6 Rankine).
Old 06-18-2004, 08:31 PM
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Default Right...but one could conciveably lower the temp by 100 deg. or so, would the air be 1.366 times...

more dense, and therefore 1.366 times the horsepower over the baseline?
Old 06-19-2004, 12:47 PM
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I dont think the increased density equates to an equivalent HP increase
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